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    Tan(A+B) = (TanA+TanB)/(1 TanATanB) Proof YouTube

    Feb 26, 2012 . simple common trig function proof.

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    ABC,3tanAtanB tanA tanB=3,(1)C_

    (1)tan(A+B)=(tanA+tanB)/(1 tanAtanB) tan(A+B)(1 tanAtanB)=tanA+tanB=3tanAtanB 3 tan(A+B)= 3,tan(180 C)= tanC,tanC=3,C=60° (2)a^2+b^2=(c/sinC)^2 (sin^2 A+sin^2 B)=16/3[ (1 cos2A)/2+(1 cos2B)/2] =16/3 8/3(cos2A +cos2B)=16/3 16/3cos(A+B)cos(A B)=16/3+8/3cos(2A 120°)

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    If A+B=π/4, then what is the value of (1+tanA) (1+tanB)? Quora

    Observe that the question is implicitly hinting that the value of the expression (1+tanA)(1+tanB) is same irrespective of the value of A and B as long as A+B=[math]\pi/4[/math]. Equipped with this little information, lets plug A=0, B=[math]\pi/4[/.

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    Using tanx=sinx/cosx, prove the addition formula for tangent, tan(A+ .

    You can put this solution on YOUR website! Since tan%28x%29=sin%28x%29%2Fcos%28x% , we can say tan%28A%2BB%29=sin%28A%2BB%29% tan%28A%2BB%29=sin%28A%2BB%29% Start with the given equation. tan%28A%2BB%29=%28sin%28A%29cos%28B Expand sine using the sum.

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